Draw a Lewis structure for (a) PH4+; (b) C2F4; (c) SbH3.
Here, we are going to draw the Lewis structure of the molecules.
Lewis structure is the representation of the valence electrons that form the bonding between atoms of a molecule and the lone pairs of electrons that may exist in the molecule.
The rules for drawing a Lewis structure.
Draw the correct skeletal structure for the molecule.Calculation of the total number of valence electronsDistribution of the electrons among the atoms to attain octets (or duets for H)If there is any atoms that is lack an octet, then form double or triple bonds to make them octet.
The electronic configuration of H(Z=1) 1s1
Valence electrons in H =1 e-
The electronic configuration of P(Z=15) [Ne] 3s23p3
Valence electrons in P =5e-
Thus, total valence electrons in PH4+ =(5 + 41 -1) =8 e-
The Lewis structure of PH4+ is given below:
Textbook: Principles of General Chemistry
Author: Martin S. Silberberg
This textbook survival guide was created for the textbook: Principles of General Chemistry, edition: 2. This full solution covers the following key subjects: draw, lewis, sbh, structure. This expansive textbook survival guide covers 23 chapters, and 1878 solutions. Since the solution to 6P from 10 chapter was answered, more than 3495 students have viewed the full step-by-step answer. Principles of General Chemistry was written by and is associated to the ISBN: 9780073511085. The full step-by-step solution to problem: 6P from chapter: 10 was answered by , our top Chemistry solution expert on 08/31/17, 03:54AM. The answer to “Draw a Lewis structure for (a) PH4+; (b) C2F4; (c) SbH3.” is broken down into a number of easy to follow steps, and 11 words.