Answer: In Exercises 1924, solve for or b
Chapter 5, Problem 24(choose chapter or problem)
In Exercises 19–24, solve for x or b.
(a) \(\log _{3} x+\log _{3}(x-2)=1\)
(b) \(\log _{10}(x+3)-\log _{10} x=1\)
Text Transcription:
log_3 x + log_3 (x - 2) = 1
log_10 (x + 3) - log_10 x = 1
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