Solution Found!
For the simple decomposition reaction How long will it
Chapter 16, Problem 31P(choose chapter or problem)
For the simple decomposition reaction
\(\mathrm{AB}(g) \longrightarrow \mathrm{A}(g)+\mathrm{B}(g)\)
\(\text { rate }=k[\mathrm{AB}]^{2}\) and \(k=0.2 \mathrm{~L} / \mathrm{mol} \cdot \mathrm{s}\). How long will it take for [AB] to reach \(\frac{1}{3}\) of its initial concentration of \(1.50 M\)?
Equation Transcription:
rate οΌ π[AB]2
π οΌ 0.2 L/mols
1.50 M
Text Transcription:
AB(g) rightarrow A(g)+B(g)
rate οΌ π[AB]^2
π οΌ 0.2 L/mols
1/3
1.50 M
Questions & Answers
QUESTION:
For the simple decomposition reaction
\(\mathrm{AB}(g) \longrightarrow \mathrm{A}(g)+\mathrm{B}(g)\)
\(\text { rate }=k[\mathrm{AB}]^{2}\) and \(k=0.2 \mathrm{~L} / \mathrm{mol} \cdot \mathrm{s}\). How long will it take for [AB] to reach \(\frac{1}{3}\) of its initial concentration of \(1.50 M\)?
Equation Transcription:
rate οΌ π[AB]2
π οΌ 0.2 L/mols
1.50 M
Text Transcription:
AB(g) rightarrow A(g)+B(g)
rate οΌ π[AB]^2
π οΌ 0.2 L/mols
1/3
1.50 M
ANSWER:
Solution 31P
Here we have to calculate the time βtβ required for [AB] to reach one-third of its initial concentration of 1.50 M .
Step 1
A simple decomposition reaction is given below,
AB (g) β A (g) + B (g)
Rate = k [AB]2Β and k = 0.2 L/mol.sΒ
From the given rate law, it has been