Solved: (a) Show that converges and diverges. (b) Compare the first five terms of each
Chapter 9, Problem 81(choose chapter or problem)
(a) Show that \(\sum_{n=2}^{\infty} \frac{1}{n^{1.1}}\) converges and \(\sum_{n=2}^{\infty} \frac{1}{n \ln n}\) diverges.
(b) Compare the first five terms of each series in part (a).
(c) Find n > 3 such that
\(\frac{1}{n^{1.1}}<\frac{1}{n \ln n}\).
Text Transcription:
sum_n=2 ^infty 1 / n^1.1
sum_n=2 ^infty 1 / n ln n
1 / n^1.1 < 1 / n ln n
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