Just answered: In Exercises 1528, use the Limit Comparison Test to determine the

Chapter 9, Problem 19

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In Exercises 15-28, use the Limit Comparison Test to determine the convergence or divergence of the series.

\(\sum_{n=1}^{\infty} \frac{2 n^{2}-1}{3 n^{5}+2 n+1}\)

Text Transcription:

sum_n=1 ^infty 2n^2 - 1 / 3n^5 + 2n + 1

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