Solution: In Exercises 5154, find the gradient of the function and the maximum value of
Chapter 13, Problem 51(choose chapter or problem)
In Exercises 51-54, find the gradient of the function and the maximum value of the directional derivative at the given point.
\(z=x^2y,\quad\ \ (2,\ 1)\)
Text Transcription:
z = x^2 y, (2, 1)
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