Solution: In Exercises 5154, find the gradient of the function and the maximum value of
Chapter 13, Problem 53(choose chapter or problem)
In Exercises 51-54, find the gradient of the function and the maximum value of the directional derivative at the given point.
\(z=\frac{y}{x^2+y^2},\ \ \ \left(1,\ 1\right)\)
Text Transcription:
z = y / x^2 + y^2, (1, 1)
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