Get answer: In Exercises 5154, find the gradient of the function and the maximum value
Chapter 13, Problem 54(choose chapter or problem)
In Exercises 51-54, find the gradient of the function and the maximum value of the directional derivative at the given point.
\(z=\frac{x^2}{x-y},\ \ \ \left(2,\ 1\right)\)
Text Transcription:
z = x^2 / x - y, (2, 1)
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