In Exercises 1–4, estimate the slope of the line from its graph. To print an enlarged copy of the graph, go to MathGraphs.com.
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Textbook Solutions for Calculus: Early Transcendental Functions
Question
In Exercises 83-86, find the distance between the point and line, or between the lines, using the formula for the distance between the point \(\left(x_{1}, y_{1}\right)\) and the line \(A x+B y+ C=0\)
Distance \(=\frac{\left|A x_{1}+B y_{1}+C\right|}{\sqrt{A^{2}+B^{2}}}\)
Point: (2, 3)
Line: 4x + 3y = 10
Text Transcription:
(x_{1}, y_{1})
Ax + By + C = 0
= |Ax_{1} + By_{1} + C| / sqrt{A^{2}+B^{2}}
Solution
The first step in solving 1.2 problem number 84 trying to solve the problem we have to refer to the textbook question: In Exercises 83-86, find the distance between the point and line, or between the lines, using the formula for the distance between the point \(\left(x_{1}, y_{1}\right)\) and the line \(A x+B y+ C=0\) Distance \(=\frac{\left|A x_{1}+B y_{1}+C\right|}{\sqrt{A^{2}+B^{2}}}\)Point: (2, 3)Line: 4x + 3y = 10Text Transcription:(x_{1}, y_{1})Ax + By + C = 0= |Ax_{1} + By_{1} + C| / sqrt{A^{2}+B^{2}}
From the textbook chapter Linear Models and Rates of Change you will find a few key concepts needed to solve this.
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