Evaluating an Expression In Exercises 1 and 2, evaluate the expressions. (a) \(25^{3 / 2}\) (b) \(81^{1 / 2}\) (c) \(3^{-2}\) (d) \(27^{-1 / 3}\) Text Transcription: 25^{3 / 2} 81^{1 / 2} 3^{-2} 27^{-1 / 3}
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Textbook Solutions for Calculus: Early Transcendental Functions
Question
For large values of \(\boldsymbol{n}\), \(n !=1 \cdot 2 \cdot 3 \cdot 4 \cdot \cdots(n-1) \cdot n\)
can be approximated by Stirling's Formula,
\(n ! \approx\left(\frac{n}{e}\right)^{n} \sqrt{2 \pi n}\)
In Exercises 131 and 132, find the exact value of \(n\) !, and then approximate \(n\) ! using Stirling's Formula.
n = 12
Text Transcription:
n
n! =1 cdot 2 cdot 3 cdot 4 cdot cdots(n - 1) cdot n
n! approx (n / e)^{n} sqrt{2 pi n}
Solution
The first step in solving 1.6 problem number 131 trying to solve the problem we have to refer to the textbook question: For large values of \(\boldsymbol{n}\), \(n !=1 \cdot 2 \cdot 3 \cdot 4 \cdot \cdots(n-1) \cdot n\)can be approximated by Stirling's Formula,\(n ! \approx\left(\frac{n}{e}\right)^{n} \sqrt{2 \pi n}\)In Exercises 131 and 132, find the exact value of \(n\) !, and then approximate \(n\) ! using Stirling's Formula.n = 12Text Transcription:n n! =1 cdot 2 cdot 3 cdot 4 cdot cdots(n - 1) cdot nn! approx (n / e)^{n} sqrt{2 pi n}
From the textbook chapter Exponential and Logarithmic Functions you will find a few key concepts needed to solve this.
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full solution