In Exercises 1-4, determine whether the differential equation is linear. Explain your reasoning. \(x^{3} y^{\prime}+x y=e^{x}+1\) Text Transcription: x^3 y^prime+x y=e^x+1
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Textbook Solutions for Calculus: Early Transcendental Functions
Question
In Exercises 43-46, match the differential equation with its solution.
Differential Equation Solution
\(y^{\prime}-2 x y=x\) (a) \(y=C e^{x^{2}}\)
(b) \(y=-\frac{1}{2}+C e^{x^{2}}\)
(c) \(y=x^{2}+C\)
(d) \(y=C e^{2 x}\)
Text Transcription:
y^prime-2 x y=x
y=C e^x^2
y=-frac 1 2+C e^x^2
y=x^2+C
y=C e^2 x
Solution
The first step in solving 6.5 problem number 46 trying to solve the problem we have to refer to the textbook question: In Exercises 43-46, match the differential equation with its solution.Differential Equation Solution\(y^{\prime}-2 x y=x\) (a) \(y=C e^{x^{2}}\) (b) \(y=-\frac{1}{2}+C e^{x^{2}}\) (c) \(y=x^{2}+C\) (d) \(y=C e^{2 x}\) Text Transcription:y^prime-2 x y=xy=C e^x^2y=-frac 1 2+C e^x^2y=x^2+Cy=C e^2 x
From the textbook chapter First-Order Linear Differential Equations you will find a few key concepts needed to solve this.
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