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Solved: Converting Moles to Number of Atoms Calculate the

Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro ISBN: 9780321809247 1

Solution for problem 2PE Chapter 3.8SE

Chemistry: A Molecular Approach | 3rd Edition

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Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro

Chemistry: A Molecular Approach | 3rd Edition

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Problem 2PE

Converting Moles to Number of Atoms Calculate the number of H atoms in 0.350 mol of C6H12O6. How many oxygen atoms are in (a) 0.25 mol Ca(NO3)2 and (b) 1.50 mol of sodium carbonate?

Step-by-Step Solution:

Answer : Step 1 We are given the amount of a substance (0.350 mol) and its chemical formula C6H12O6. The unknown is the number of H atoms in the sample. Avogadro’s number provides the conversion factor between number of moles of C6H12O6 and number of molecules of C6H12O6: 1 mol C6H12O6 = 6.02 * 10^23 molecules of C6H12O6. Once we know the number of molecules of C6H12O6, we can use the chemical formula, which tells us that each molecule of C6H12O6 contains 12 H atoms. Thus, we convert moles of C6H12O6 to molecules of C6H12O6 and then determine the number of atoms of H from the number of molecules of C6H12O6: Moles C6H12O6 molecules C6H12O6 atoms H. H atoms =(0.350 mol C6H12O6)(6.023*10 molecules of C6H12O6)/1 mole of C6H12O6)*(12 H atoms )/(1 molecule of C6H12O6). =2.53*10 H atoms . Step 2 Before solving the problem we have to know about the avogadro's number . the number of atoms or molecules in one mole of a substance, equal to 6.023 × 10 . 23 Avogadro's number is the conversion factor between number of moles of Ca(NO3)2and number of molecules of Ca(NO3)2 . One mole of Ca(NO3)2=6.023*10 .molecules of Ca(NO3)2 . Chemical formula of Ca(NO3)2 tell us that it contains 6 oxygen atoms. Number of O atoms ={0.25 mol Ca(NO3)2}*{6.023*10 molecules Ca(NO3)2/1 mol Ca(NO3)2}.*{6 ‘O’ atoms /1 molecule Ca(NO3)2}. =9.0*10 O’ atoms. 23 So there is 9.0*10 oxygen atoms present in 0.25 mol Ca(NO3)2.

Step 3 of 3

Chapter 3.8SE, Problem 2PE is Solved
Textbook: Chemistry: A Molecular Approach
Edition: 3
Author: Nivaldo J. Tro
ISBN: 9780321809247

Chemistry: A Molecular Approach was written by and is associated to the ISBN: 9780321809247. This textbook survival guide was created for the textbook: Chemistry: A Molecular Approach, edition: 3. This full solution covers the following key subjects: atoms, mol, carbonate, Converting, calculate. This expansive textbook survival guide covers 82 chapters, and 9464 solutions. The full step-by-step solution to problem: 2PE from chapter: 3.8SE was answered by , our top Chemistry solution expert on 02/22/17, 04:35PM. Since the solution to 2PE from 3.8SE chapter was answered, more than 346 students have viewed the full step-by-step answer. The answer to “Converting Moles to Number of Atoms Calculate the number of H atoms in 0.350 mol of C6H12O6. How many oxygen atoms are in (a) 0.25 mol Ca(NO3)2 and (b) 1.50 mol of sodium carbonate?” is broken down into a number of easy to follow steps, and 34 words.

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