At least 25 J.lg of tetrahydrocannabinol (THC), the active ingredient in marijuana, is
Chapter 3, Problem 3.42(choose chapter or problem)
At least 25 J.lg of tetrahydrocannabinol (THC), the active ingredient in marijuana, is required to produce intoxication. The molecular formula of THC is C21H3o02. How many moles of THC does this 25 J.lg represent? How many molecules?
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