Calculate the enthalpy change for the reaction P406(s) + 2 02(gl ----+ P4010(s) given
Chapter 5, Problem 5.61(choose chapter or problem)
Calculate the enthalpy change for the reaction P406(s) + 2 02(gl ----+ P4010(s) given the following enthalpies of reaction: P4(s) + 3 02(g) ----+ P406(s) P4(s) + 5 02(g) ----+ P4010(s) !lH = -1640.1 kj !lH = -2940.1 kj
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer