The precipitation reaction between AgN03(aq) and NaCl(aq) proceeds as follows: AgN03(aq)
Chapter 5, Problem 5.117(choose chapter or problem)
The precipitation reaction between AgN03(aq) and NaCl(aq) proceeds as follows: AgN03(aq) + NaCl(aq) ----> NaN03(aq) + AgCl(s) (a) By using Appendix C, calculate !lH0 for the net ionic equation of this reaction. (b) What would you expect for the value of t.Ho of the overall molecular equation compared to that for the net ionic equation? Explain. (c) Use the results from (a) and (b) along with data in Appendix C to determine the value of t.HJ for AgN03(aq).
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