The solubility of Cr(N03h 9 HzO in water is 208 g per 100 g of water at 15 oc. A
Chapter 13, Problem 13.21(choose chapter or problem)
The solubility of Cr(N03h 9 HzO in water is 208 g per 100 g of water at 15 oc. A solution of Cr(N03h 9 H20 in water at 35 oc is formed by dissolving 324 g in 100 g water. When this solution is slowly cooled to 15 C, no precipitate forms. (a) What term describes this solution? (b) What action might you take to initiate crystallization? Use molecular-level processes to explain how your suggested procedure works.
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