Use the prefix multipliers to express each measurement without any exponents.
b. 22 x 10-15 s
c. 1.5 x 109 g
d. 3.5X106 L
Step 1 of 3
Solution 55E Here, we have to calculate the mass of the air in room We know Density defines the mass per unit time Density = Mass/ Volume According to question Density of air = 1.19 g/L 3 Volume = 14.5 ft * 16.5 ft * 8.0 ft =1914 ft Now, we have to convert the volume ft to L3 1 ft3 = 28.317 L Therefore the volume in L = 1914 ft x3 28.317 = 54198.74 L 1 ft3 Thus Mass Density = volume Mass = Density x volume = 1.19 g/L x 54198.74 L = 64496.5 g Now convert the mass from g to kg We know 1000 g = 1 kg 1 kg The mass of the air in kg = 64496.5 gg x 1000g = 64.5 kg Thus, the mass of the air in that room is 64.5 kg
Textbook: Chemistry: A Molecular Approach
Author: Nivaldo J. Tro
The full step-by-step solution to problem: 55E from chapter: 1 was answered by , our top Chemistry solution expert on 02/22/17, 04:35PM. Chemistry: A Molecular Approach was written by and is associated to the ISBN: 9780321809247. This textbook survival guide was created for the textbook: Chemistry: A Molecular Approach, edition: 3. The answer to “Use the prefix multipliers to express each measurement without any exponents.a. 1.2xl0-9mb. 22 x 10-15 sc. 1.5 x 109 gd. 3.5X106 L” is broken down into a number of easy to follow steps, and 22 words. This full solution covers the following key subjects: air, mass, Atmospheric, Density, Dimensional. This expansive textbook survival guide covers 82 chapters, and 9454 solutions. Since the solution to 55E from 1 chapter was answered, more than 442 students have viewed the full step-by-step answer.