For Problems 14 determine the order of the differential equation.d2 y dx2 + x dy dx + y = ex .
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Textbook Solutions for Differential Equations and Linear Algebra
Question
Any curve with the property that whenever it intersects a curve of a given family it does so at an angle a = /2 is called an oblique trajectory of the given family. (See Figure 1.1.7.) Let m1 (equal to tan a1) denote the slope of the required family at the point (x, y), and let m2 (equal to tan a2) denote the slope of the given family. Show that m1 = m2 tan a 1 + m2 tan a . [Hint: From Figure 1.1.7, tan a1 = tan(a2a)]. Thus, the equation of the family of oblique trajectories is obtained by solving dy dx = m2 tan a 1 + m2 tan a . Curve of given family m1 5 tan a1 5 slope of required family m2 5 tan a2 5 slope of given family a1 a2 a Curve of required family Figure 1.1.7: Oblique trajectories intersect at an angle a.
Solution
The first step in solving 1.1 problem number 23 trying to solve the problem we have to refer to the textbook question: Any curve with the property that whenever it intersects a curve of a given family it does so at an angle a = /2 is called an oblique trajectory of the given family. (See Figure 1.1.7.) Let m1 (equal to tan a1) denote the slope of the required family at the point (x, y), and let m2 (equal to tan a2) denote the slope of the given family. Show that m1 = m2 tan a 1 + m2 tan a . [Hint: From Figure 1.1.7, tan a1 = tan(a2a)]. Thus, the equation of the family of oblique trajectories is obtained by solving dy dx = m2 tan a 1 + m2 tan a . Curve of given family m1 5 tan a1 5 slope of required family m2 5 tan a2 5 slope of given family a1 a2 a Curve of required family Figure 1.1.7: Oblique trajectories intersect at an angle a.
From the textbook chapter Differential Equations Everywhere you will find a few key concepts needed to solve this.
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