Answer: Let b0, b1, b2,... be the sequence defined by the explicit formula bn = C 3n +
Chapter 5, Problem 6(choose chapter or problem)
Let \(b_{0}, b_{1}, b_{2}\), . . . be the sequence defined by the explicit formula
\(b_{n} = C \cdot 3^{n} + D(−2)^{n}\) for all integers n ≥ 0,
where C and D are real numbers. Show that for any choice of C and D,
\(b_{k} = b_{k−1} + 6b_{k−2}\) for all integers k ≥ 2.
Text Transcription:
b_0, b_1, b_2
b_n = C cdot 3^n + D(−2)^n
b_k = b_k−1 + 6b_k−2
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