If b is any positive real number with b = 1 and x is any real number, bx is defined as
Chapter 7, Problem 21(choose chapter or problem)
If b is any positive real number with \(b \neq 1\) and x is any real number, \(b^{-x}\) is defined as follows: \(b^{-x}=\frac{1}{b^{x}}\). Use this definition and the definition of logarithm to prove that \(\log _{b}\left(\frac{1}{u}\right)=-\log _{b}(u)\) for all positive real numbers u and b, with \(b \neq 1\).
Text Transcription:
b neq 1
b^-x
b^-x =1/b^x
log _b (1/u)=-log_b (u)
b neq 1
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