At time t = 10 s, the velocity of a particle moving in thex-y plane is v = 0.1i + 2j m | StudySoup

Textbook Solutions for Engineering Mechanics: Dynamics

Chapter 2 Problem 2/59

Question

(In the following problems where motion as a projectile in air is involved, neglect air resistance unless otherwise stated and use \(g=9.81 \mathrm{~m} / \mathrm{s}^2\) or \(g=32.2 \mathrm{ft} / \mathrm{sec}^2\).)

At time \(t=10 \mathrm{~s}\), the velocity of a particle moving in the x-y plane is \(\mathbf{v}=0.1 \mathbf{i}+2 \mathbf{j ~ m} / \mathrm{s}\). By time \(t=10.1 \mathrm{~s}\), its velocity has become \(-0.1 \mathbf{i}+1.8 \mathbf{j ~ m} / \mathrm{s}\). Determine the magnitude \(a_{\mathrm{av}}\) of its average acceleration during this interval and the angle \(\theta\) made by the average acceleration with the positive x-axis.

Solution

Step 1 of 4)

The first step in solving 2 problem number 59 trying to solve the problem we have to refer to the textbook question: (In the following problems where motion as a projectile in air is involved, neglect air resistance unless otherwise stated and use \(g=9.81 \mathrm{~m} / \mathrm{s}^2\) or \(g=32.2 \mathrm{ft} / \mathrm{sec}^2\).)At time \(t=10 \mathrm{~s}\), the velocity of a particle moving in the x-y plane is \(\mathbf{v}=0.1 \mathbf{i}+2 \mathbf{j ~ m} / \mathrm{s}\). By time \(t=10.1 \mathrm{~s}\), its velocity has become \(-0.1 \mathbf{i}+1.8 \mathbf{j ~ m} / \mathrm{s}\). Determine the magnitude \(a_{\mathrm{av}}\) of its average acceleration during this interval and the angle \(\theta\) made by the average acceleration with the positive x-axis.
From the textbook chapter KINEMATICS OF PARTICLES you will find a few key concepts needed to solve this.

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full solution

Title Engineering Mechanics: Dynamics 8 
Author James L. Meriam, L. G. Kraige, J. N. Bolton
ISBN 9781118885840

At time t = 10 s, the velocity of a particle moving in thex-y plane is v = 0.1i + 2j m

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