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Assume that an exhaled breath of air consists of 74.8% N2,
Chapter , Problem 10.108(choose chapter or problem)
Assume that an exhaled breath of air consists of 74.8% N2, 15.3% O2, 3.7% CO2, and 6.2% water vapor. (a) If the total pressure of the gases is 0.985 atm, calculate the partial pressure of each component of the mixture. (b) If the volume of the exhaled gas is 455 mL and its temperature is 37 C, calculate the number of moles of CO2 exhaled. (c) How many grams of glucose 1C6H12O62 would need to be metabolized to produce this quantity of CO2? (The chemical reaction is the same as that for combustion of C6H12O6. See Section 3.2 and 10.57.)
Questions & Answers
QUESTION:
Assume that an exhaled breath of air consists of 74.8% N2, 15.3% O2, 3.7% CO2, and 6.2% water vapor. (a) If the total pressure of the gases is 0.985 atm, calculate the partial pressure of each component of the mixture. (b) If the volume of the exhaled gas is 455 mL and its temperature is 37 C, calculate the number of moles of CO2 exhaled. (c) How many grams of glucose 1C6H12O62 would need to be metabolized to produce this quantity of CO2? (The chemical reaction is the same as that for combustion of C6H12O6. See Section 3.2 and 10.57.)
ANSWER:Problem 10.108Assume that an exhaled breath of air consists of 74.8% N , 15.3% O , 3.7% CO , and 6.2% 2 2 2water vapor. (a) If the total pressure of the gases is 0.985 atm, calculate the partial pressure ofeach component of the mixture. (b) If the volume of the exhaled gas is 455 mL and itstemperature is 37 °C, calculate the number of moles of CO exhaled. (c) How man2 grams ofglucose C H 6 12)6ould need to be metabolized to produce this quantity of CO (The 2chemical reaction is the same as that for combustion of C H O . See Sec6o12.26nd 10.57.) Step-by-step solution Step 1 of 7 ^The composition of exhaled air is as follows: 74.8% N ; 15.3 O ; 3.2 CO ; and2.2% water 2vapor. The total pressure of all these gases is 0.985 atm.