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The circuit shown in Figure P 8.4-2 is at steady state before the switch closes at time
Chapter 8, Problem P8.4-2(choose chapter or problem)
The circuit shown in Figure P 8.4-2 is at steady state before the switch closes at time t = 0. The switch remains closed for 1.5 s and then opens. Determine the inductor current i(t) for t > 0.
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QUESTION:
The circuit shown in Figure P 8.4-2 is at steady state before the switch closes at time t = 0. The switch remains closed for 1.5 s and then opens. Determine the inductor current i(t) for t > 0.
Step 1 of 6
The given circuit is a first-order circuit whose output is the current through the inductor. It can be expressed as:
\(i(t)=I_{s c}+\left(i\left(0^{+}\right)-I_{s c}\right) e^{-\frac{t}{\tau} \ldots\ldots(1)}\)
The circuit is at a steady state when the switch is open. The inductor acts as a short circuit. The schematic for this case is shown below.
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