A band-pass filter has two cutoff frequencies, oa and ob. Suppose that oa is quite a bit smaller than ob, say oa < ob=10. Let HL(s) be a low-pass transfer function having a cutoff frequency equal to ob and HH(s) be a high-pass transfer function having a cutoff frequency equal to oa. A band-pass transfer function can be obtained as a product of low-pass and high-pass transfer functions, HB(s) HL(s) HH(s). The order of the band-pass filter is equal to the sum of the orders of the low-pass and high-pass filters. We usually make the orders of the low-pass and high-pass filter equal, in which case the order of the band-pass is even. The pass-band gain of the bandpass filter is the product of pass-band gains of the low-pass and high-pass transfer functions. Obtain the transfer function of a fourth-order band-pass filter having cutoff frequencies equal to 100 rad/s and 2000 rad/s and a pass-band gain equal to 4.

PY 205 Week 5 Newton’s Law of Universal Gravitation - The force of gravitation exerted on one particle by a second particle is always directed toward the second particle o The total force on one particle is the vector sum of the forces exerted by each of the others - Gravity near the earth’s surface o The force of gravity due to...