Solution Found!
(a) Show that the flow velocity measured by a venturi
Chapter 4, Problem 47P(choose chapter or problem)
(III) (a) Show that the flow velocity measured by a venturi meter (see Fig. ) is given by the relation
\(v_{1}=A_{2} \sqrt{\frac{2\left(P_{1}-P_{2}\right)}{\rho\left(A_{1}^{2}-A_{2}^{2}\right)}}\)
(b) A venturi tube is measuring the flow of water; it has a main diameter of tapering down to a throat diameter of
. If the pressure difference is measured to be
, what is the velocity of the water?
Equation Transcription:
Text Transcription:
v_1=A_2 \sqrt{\frac{2(P_1-P_2)\rho(A_1^2-A_2^2)
Questions & Answers
QUESTION:
(III) (a) Show that the flow velocity measured by a venturi meter (see Fig. ) is given by the relation
\(v_{1}=A_{2} \sqrt{\frac{2\left(P_{1}-P_{2}\right)}{\rho\left(A_{1}^{2}-A_{2}^{2}\right)}}\)
(b) A venturi tube is measuring the flow of water; it has a main diameter of tapering down to a throat diameter of
. If the pressure difference is measured to be
, what is the velocity of the water?
Equation Transcription:
Text Transcription:
v_1=A_2 \sqrt{\frac{2(P_1-P_2)\rho(A_1^2-A_2^2)
ANSWER:
ANSWER:Weight of the elevator is 2500 N.By definition of weight, it is the normal reaction an object gets.So, N = mg = mass × 9.8 = 2500 mass = 2500/9.8 = 245 kg .But