Suppose v,w Rn and c is a scalar. Prove that Span (v + cw,w) = Span (v,w). (See the blue | StudySoup

Textbook Solutions for Linear Algebra: A Geometric Approach

Chapter 1.1 Problem 21

Question

Suppose \(\mathbf{v}, \mathbf{w} \in \mathbb{R}^{n}\) and c is a scalar. Prove that \(\operatorname{Span}(\mathbf{v}+c \mathbf{w}, \mathbf{w})=\operatorname{Span}(\mathbf{v}, \mathbf{w})\). (See the blue box on p. 12.)

Solution

Step 1 of 2

Suppose \(v, w \in R^{n}\) and  \(c\) is a scalar.

Let \(U \in \operatorname{Span}(v+c w, w)\). Then there exist scalars \(c_{1}, c_{2}\) such that \(u=c_{1}(v+c w)+c_{2} w\)

Observe that \(c_{1}(v+c w)+c_{2} w\)

\(\begin{array}{l} =c_{1} v+c_{1}(c w)+c_{2} w \\ =c_{1} v+c_{1} c w+c_{2} w \\ =c_{1} v+\left(c_{1} c+c_{2}\right) w \\ u=c_{1} v+\left(c_{1} c+c_{2}\right) w \end{array}\)

and therefore \(u \in \operatorname{Span}(v, w)\)

Thus ,\(\operatorname{Span}(v+c w, w) \subset \operatorname{Span}(v, w)\).

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full solution

Title Linear Algebra: A Geometric Approach 2 
Author Ted Shifrin, Malcolm Adams
ISBN 9781429215213

Suppose v,w Rn and c is a scalar. Prove that Span (v + cw,w) = Span (v,w). (See the blue

Chapter 1.1 textbook questions

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