Find a basis for each of the given subspaces and determine its dimension. a. \(V=\operatorname{Span}((1,2,3),(3,4,7),(5,-2,3)) \subset \mathbb{R}^{3}\) b. \(V=\left\{\mathbf{x} \in \mathbb{R}^{4}: x_{1}+x_{2}+x_{3}+x_{4}=0, x_{2}+x_{4}=0\right\} \subset \mathbb{R}^{4}\) c. \(V=(\operatorname{Span}((1,2,3)))^{\perp} \subset \mathbb{R}^{3}\) d. \(V=\left\{\mathbf{x} \in \mathbb{R}^{5}: x_{1}=x_{2}, x_{3}=x_{4}\right\} \subset \mathbb{R}^{5}\)
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Textbook Solutions for Linear Algebra: A Geometric Approach
Question
In each case, construct a matrix with the requisite properties or explain why no such matrix exists.
a. The column space has basis \(\left[\begin{array}{l} 1 \\ 0 \\ 1 \end{array}\right]\), and the nullspace contains \(\left[\begin{array}{l} 1 \\ 2 \\ 0 \end{array}\right]\).
b. The nullspace contains \(\left[\begin{array}{l} 1 \\ 0 \\ 1 \end{array}\right]\), \(\left[\begin{array}{r} -1 \\ 2 \\ 1 \end{array}\right]\), and the row space contains \(\left[\begin{array}{r} 1 \\ 1 \\ -1 \end{array}\right]\).
c. The column space has basis \(\left[\begin{array}{l} 1 \\ 0 \\ 1 \end{array}\right]\), \(\left[\begin{array}{l} 0 \\ 1 \\ 1 \end{array}\right]\), and the row space has basis \(\left[\begin{array}{l} 1 \\ 1 \\ 1 \end{array}\right]\), \(\left[\begin{array}{l} 2 \\ 0 \\ 1 \end{array}\right]\).
d. The column space and the nullspace both have basis \(\left[\begin{array}{l} 1 \\ 0 \end{array}\right]\).
e. The column space and the nullspace both have basis \(\left[\begin{array}{l} 1 \\ 0 \\ 0 \end{array}\right]\)
Solution
Step 1 of 9
Row Space, also known as a span of rows, is the collection of all linear combinations of its rows. Column space is the sum of all possible linear arrangements of a given set of columns, or span of columns. Null space is the collection of all homogeneous equation solutions.
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