Solution Found!
Show that if is an eigenvalue of the 2 2 matrix _ a b c d and either b _= 0 or _= a
Chapter 6, Problem 5(choose chapter or problem)
Show that if \(\lambda\) is an eigenvalue of the \(2\ \times\ 2\) matrix \(\left[\begin{array}{ll} a & b \\ c & d \end{array}\right]\) and either \(b\ \neq\ 0\ \text{or}\ \lambda\ \neq\ a\), then \(\left[\begin{array}{c} b \\ \lambda-a \end{array}\right]\) is a corresponding eigenvector.
Questions & Answers
QUESTION:
Show that if \(\lambda\) is an eigenvalue of the \(2\ \times\ 2\) matrix \(\left[\begin{array}{ll} a & b \\ c & d \end{array}\right]\) and either \(b\ \neq\ 0\ \text{or}\ \lambda\ \neq\ a\), then \(\left[\begin{array}{c} b \\ \lambda-a \end{array}\right]\) is a corresponding eigenvector.
ANSWER:Step 1 of 3
Show that 
It is known that 
To find the eigenvector of 
