Solved: The exact solution of the system 0.6000x1 + 2000x2 = 2003 0.3076x1 0.4010x2 =
Chapter 7, Problem 7(choose chapter or problem)
The exact solution of the system 0.6000x1 + 2000x2 = 2003 0.3076x1 0.4010x2 = 1.137 is x = (5, 1)T . Suppose that the calculated value of x2 is x 2 = 1 + e. Use this value in the first equation and solve for x1. What will the error be? Calculate the relative error in x1 if e = 0.001.
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