If IQ(-YS) is viewed in terms of Theorem 42.1, then p(x) = x3 - 5 [choosing p(x) to
Chapter 42, Problem 42.12(choose chapter or problem)
If IQ(-YS) is viewed in terms of Theorem 42.1, then p(x) = x3 - 5 [choosing p(x) to bemonic]. Verify that although -Y5 E 1Q-Y5)), p(x) has roots that are not in 1Q(-Y5). (Thus asimple algebraic extension is not necessarily an algebraic extension as defined in Section 32.)
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