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The radius of the earths orbit around the sun (assumed to
Chapter 3, Problem 3.28(choose chapter or problem)
The radius of the earth’s orbit around the sun (assumed to be circular) is \(1.50\times 10^8\mathrm{\ km}\) and the earth travels around this orbit in 365 days.
(a) What is the magnitude of the orbital velocity of the earth, in m/s?
(b) What is the radial acceleration of the earth toward the sun, in \(\mathrm{m} / \mathrm{s}^{2} \text { ? }\)
(c) Repeat parts (a) and (b) for the motion of the planet Mercury (\(\text{ orbit radius }=5.79\times 10^7\mathrm{\ km}\text{, }\text{orbital period }=88.0\text{ days }\))..
Questions & Answers
QUESTION:
The radius of the earth’s orbit around the sun (assumed to be circular) is \(1.50\times 10^8\mathrm{\ km}\) and the earth travels around this orbit in 365 days.
(a) What is the magnitude of the orbital velocity of the earth, in m/s?
(b) What is the radial acceleration of the earth toward the sun, in \(\mathrm{m} / \mathrm{s}^{2} \text { ? }\)
(c) Repeat parts (a) and (b) for the motion of the planet Mercury (\(\text{ orbit radius }=5.79\times 10^7\mathrm{\ km}\text{, }\text{orbital period }=88.0\text{ days }\))..
ANSWER:Step 1 of 9
Equation for speed in centripetal motion, v = distance /time =
Where, - circumference of the circular path
T - Time taken to cover this circular path