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Solved: The average time it takes for a molecule to

Chapter 1, Problem 94P

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QUESTION:

The average time it takes for a molecule to diffuse a distance of \(x \ cm\) is given by

                                \(t=\frac{x^{2}}{2 D}\)

where \(t\) is the time in seconds and \(D\) is the diffusion coefficient. Given that the diffusion coefficient of glucose is \(5.7\times10^{-7}\mathrm{\ cm}^2/\mathrm{s}\), calculate the time it would take for a glucose molecule to diffuse \(10\ \mu\mathrm{m}\), which is roughly the size of a cell.

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QUESTION:

The average time it takes for a molecule to diffuse a distance of \(x \ cm\) is given by

                                \(t=\frac{x^{2}}{2 D}\)

where \(t\) is the time in seconds and \(D\) is the diffusion coefficient. Given that the diffusion coefficient of glucose is \(5.7\times10^{-7}\mathrm{\ cm}^2/\mathrm{s}\), calculate the time it would take for a glucose molecule to diffuse \(10\ \mu\mathrm{m}\), which is roughly the size of a cell.

ANSWER:

Step 1 of 2

Here, we are going to calculate the time taken for the glucose to diffuse.

 

Given that,

 

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