Solution Found!
Answer: Ethane and acetylene are two gaseous hydrocarbons.
Chapter 2, Problem 108P(choose chapter or problem)
Ethane and acetylene are two gaseous hydrocarbons. Chemical analyses show that in one sample of ethane, 2.65 g of carbon are combined with 0.665 g of hydrogen, and in one sample of acetylene, 4.56 g of carbon are combined with 0.383 g of hydrogen. (a) Are these results consistent with the law of multiple proportions? (b) Write reasonable molecular formulas for these compounds.
Questions & Answers
QUESTION:
Ethane and acetylene are two gaseous hydrocarbons. Chemical analyses show that in one sample of ethane, 2.65 g of carbon are combined with 0.665 g of hydrogen, and in one sample of acetylene, 4.56 g of carbon are combined with 0.383 g of hydrogen. (a) Are these results consistent with the law of multiple proportions? (b) Write reasonable molecular formulas for these compounds.
ANSWER:Step 1 of 3
Here we have to explain that the given amount of C and H present in ethane and acetylene consistent with the law of multiple proportions or not. Along with that we have to write the molecular formula of this compounds.
Law of Multiple proportion:
Law of multiple proportion states that, the two elements will combine to form a compound in such a way that the weight of one element that combine with fixed weight weight of other are in a ratio of small whole numbers.
For example:
Let us consider O-atom in NO and in \(NO_2\). Here the mass of N-atom is fixed in both the cases.
Oxygen of NO : Oxygen of \(NO_2\)
1.143 :2.286
1.143/1.143 : 2.286/1.143
1:2 (whole number ratio)
Hence we can say that this two molecules satisfied the Law of multiple proportion.