If the DG0 for a reaction is 24.5 kcal/mol at 298 K, what is the Keq for this reaction? Whatis the change in entropy of this reaction if DH0 5 23.2 kcal/mol?

ICE Tables Friday, January 26, 2018 3:50 PM K pK cRT) . n N = change of moles of GAS K p Equilibrium constant for pressure K c Equilibrium constant for concentration R = 0.08201 Lxatm/molxK T = Temperature in Kelvin Q - the ratio pf products to reactants (to the power of their stoichiometric coefficients) of concentrations or activity at any give time If Q < eq ---> not enough products If Q = eq ---> reaction is at equilibrium If Q > eq ---> Too many products ICE = Initial Change Equilibrium Reaction: N 2 O 2--> 2NO In this problem, we start with 2 mol of N and O 2 2 N2 O2 2NO Initial 2 2 0 Change -x -x +2x Equilibrium 2-x 2-x 2x Kc= [NO] / [N2][NO2] 2 2 4 = 2x /(2-x) Le Chatelier's Principle ICE Tables Friday, January 26, 2018 3:50 PM K pK cRT) . n N = change of moles of GAS K p Equilibrium constant for pressure K c Equilibrium constant for concentration R = 0.08201 Lxatm/molxK T = Temperature in Kelvin Q - the ratio pf products to reactants (to the power of their stoichiometric coefficients) of concentrations or activity at any give time If Q < eq ---> not enough products If Q = eq ---> reaction is at equilibrium If Q > eq ---> Too many products ICE = Initial Change Equilibrium Reaction: N 2 O 2--> 2NO In this problem, we start with 2 mol of N and O