Chapter : Problem 7
Calculus: Early Transcendentals 9
The set of all points within a perpendicular distance \(r\) from a smooth simple curve \(C\) in \(R^3 \) form a "tube," which we denote by Tube \((C,r)\); see the figure at the left. (We assume that \(r\) is small enough that the tube does not intersect itself.) It may seem that the volume of such a tube would depend on the twists and turns of \(C\), but in this problem you will find a formula for the volume of Tube \(C,r)\) which, perhaps surprisingly, depends only on \(r\) and the length of \(C\). We assume that \(C\) is parameterized with respect to arc length \(s\) as \(r(s)\), where \(a \leqslant s \leqslant b\) so the arc length of \(C\) is \(L=b-a\).
(a) Show that the surface of Tube \((C, q)\) is parameterized by
\(X(u, v)=r(u)+q \cos v N(u)+q \sin v B(u)\) \(\quad\) \(\quad\) \(\quad\) \(a \leqslant u \leqslant b, 0 \leqslant v \leqslant 2 \pi\)
a. First choice b. 2nd choice
c. 3rd choice d. None of the above
where \(N\) and \(B\) are the unit normal and binormal vectors for \(C\).
(b) Use the Frenet-Serret Formulas (Exercises 13.3.71-72) and the Pythagorean Theorem for vectors (Exercise 12.3.66) to show that
\(\left|X_{u}(u, v) \times X_{v}(u, v)\right|=q[1-\kappa(u) q \cos v]\)
and so the surface area of Tube \((C,q)\) is
\(S(q)=\int_{a}^{b} \int_{0}^{2 \pi}\left|X_{u}(u, v) \times X_{v}(u, v)\right| d v d u=2 \pi q L\)
(c) Consider a thin tubular shell of radius \(q\) and thickness \(\delta q\) along \(C\), a cross-section of which is shown in the figure.
Observe that the volume of the shell is approximately \(\Delta q S(q)\) and conclude that the volume of Tube \((C, r)\) is
\(\int_{0}^{r} S(q) d q=\pi r^{2} L\)
(d) Find the volume of a tube of radius \(r=0.2\) around the helix \(r(t)=\langle\cos t, \sin t, t\rangle\), \(0 \leqslant t \leqslant 4 \pi\)
(e) Find the volume of the torus in Example 8.3.7.
Equation Transcription:
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Text Transcription:
r
C
R^3
(C, r)
r
C
(C, r)
r
C
C
s
r(s)
a leqslant s leqslant b
C
L=b-a
(C, q)
X(u,v)=r(u)+q cos v N(u) + q sin v B(u) a leqslant u leqslant b, 0 leqslant v leqslant 2pi
N
B
C
|X_u (u,v) x X_v (u,v)| =q[1-k(u)q cos v]
(C, q)
S(q)=integral _a ^b integral _0 ^2pi |X_u (u,v) x X_v (u, v)| dvdu=2pi q L
q
nabla q
C
nabla q S(q)
(C, r)
integral _0 ^r S(q) dq=pi r^2 L
r=0.2
r(t) = langle cos t, sin t, t rangle
0 leqslant t leqslant 4pi
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