Solution Found!
The article “Evaluation of a Ventilation Strategy to
Chapter 1, Problem 9E(choose chapter or problem)
The article “Evaluation of a Ventilation Strategy to Prevent Barotrauma in Patients at High Risk for Acute Respiratory Distress Syndrome” (New Engl. J. of Med., 1998: 355–358) reported on an experiment in which 120 patients with similar clinical features were randomly divided into a control group and a treatment group, each consisting of 60 patients. The sample mean ICU stay (days) and sample standard deviation for the treatment group were 19.9 and 39.1, respectively, whereas these values for the control group were 13.7 and 15.8. a. Calculate a point estimate for the difference between true average ICU stay for the treatment and control groups. Does this estimate suggest that there is a significant difference between true average stays under the two conditions? b. Answer the question posed in part (a) by carrying out a formal test of hypotheses. Is the result different from what you conjectured in part (a)? c. Does it appear that ICU stay for patients given the ventilation treatment is normally distributed? Explain your reasoning. d. Estimate true average length of stay for patients given the ventilation treatment in a way that conveys information about precision and reliability.
Questions & Answers
QUESTION:
The article “Evaluation of a Ventilation Strategy to Prevent Barotrauma in Patients at High Risk for Acute Respiratory Distress Syndrome” (New Engl. J. of Med., 1998: 355–358) reported on an experiment in which 120 patients with similar clinical features were randomly divided into a control group and a treatment group, each consisting of 60 patients. The sample mean ICU stay (days) and sample standard deviation for the treatment group were 19.9 and 39.1, respectively, whereas these values for the control group were 13.7 and 15.8. a. Calculate a point estimate for the difference between true average ICU stay for the treatment and control groups. Does this estimate suggest that there is a significant difference between true average stays under the two conditions? b. Answer the question posed in part (a) by carrying out a formal test of hypotheses. Is the result different from what you conjectured in part (a)? c. Does it appear that ICU stay for patients given the ventilation treatment is normally distributed? Explain your reasoning. d. Estimate true average length of stay for patients given the ventilation treatment in a way that conveys information about precision and reliability.
ANSWER:Q: The article “Evaluation of a Ventilation Strategy to Prevent Barotrauma in Patients at HighRisk for Acute Respiratory Distress Syndrome” (New Engl. J. of Med., 1998: 355–358) reportedon an experiment in which 120 patients with similar clinical features were randomly divided intoa control group and a treatment group, each consisting of 60 patients. The sample mean ICU stay(days) and sample standard deviation for the treatment group were 19.9 and 39.1, respectively,whereas these values for the control group were 13.7 and 15.8. a. Calculate a point estimate forthe difference between true average ICU stay for the treatment and control groups. Does thisestimate suggest that there is a significant difference between true average stays under the twoconditions b. Answer the question posed in part (a) by carrying out a formal test of hypotheses.Is the result different from what you conjectured in part (a) c. Does it appear that ICU stay forpatients given the ventilation treatment is normally distributed Explain your reasoning. d.Estimate true average length of stay for patients given the ventilation treatment in a way thatconveys information about precision and reliability. Step By Step SolutionStep 1 of 5:Given data:$S_1=39.1 _1=39.1 =39.1 9.1 1 $