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Consider purchasing a system of audio components

Probability and Statistics for Engineers and the Scientists | 9th Edition | ISBN: 9780321629111 | Authors: Ronald E. Walpole; Raymond H. Myers; Sharon L. Myers; Keying E. Ye ISBN: 9780321629111 32

Solution for problem 84E Chapter 2

Probability and Statistics for Engineers and the Scientists | 9th Edition

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Probability and Statistics for Engineers and the Scientists | 9th Edition | ISBN: 9780321629111 | Authors: Ronald E. Walpole; Raymond H. Myers; Sharon L. Myers; Keying E. Ye

Probability and Statistics for Engineers and the Scientists | 9th Edition

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Problem 84E

Consider purchasing a system of audio components consisting of a receiver, a pair of speakers, and a CD player. Let A1 be the event that the receiver functions properly throughout the warranty period, A2 be the event that the speakers function properly throughout the warranty period, and A3 be the event that the CD player functions properly throughout the warranty period. Suppose that these events are (mutually) independent with P(A1) = .95, P(A2) = .98, and P(A3) = .80. a. What is the probability that all three components function properly throughout the warranty period? b. What is the probability that at least one component needs service during the warranty period? c. What is the probability that all three components need service during the warranty period? d. What is the probability that only the receiver needs service during the warranty period? e. What is the probability that exactly one of the three components needs service during the warranty period? f. What is the probability that all three components function properly throughout the warranty period but that at least one fails within a month after the warranty expires?

Step-by-Step Solution:

Answer Step 1 of 7 P(A )10.95 P(A )11-0.95=0.05, 1 P(A )20.98 P(A ) =1-0.982.02, P(A ) =0.8 P(A ) =1-0.8=0.2, 3 3 Step 2 of 7 a) The probability that all three components function properly throughout the warranty period = P(A1). P(A2). P(A3) =0.95(0.98)(0.8) = 0.745 Step 3 of 7 b) The probability that at least one component needs service during the warranty period =1-P(A1). P(A2). P(A3) =1- 0.745 =0.255 Step 4 of 7 c) The probability that all three components need service during the warranty period = P(A ). P(A ) . P(A ) 1 1 2 3 =0.05(0.02)(0.2) =0.0002

Step 5 of 7

Chapter 2, Problem 84E is Solved
Step 6 of 7

Textbook: Probability and Statistics for Engineers and the Scientists
Edition: 9
Author: Ronald E. Walpole; Raymond H. Myers; Sharon L. Myers; Keying E. Ye
ISBN: 9780321629111

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Consider purchasing a system of audio components

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