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The actual tracking weight of a stereo cartridge that is

Probability and Statistics for Engineers and the Scientists | 9th Edition | ISBN: 9780321629111 | Authors: Ronald E. Walpole; Raymond H. Myers; Sharon L. Myers; Keying E. Ye ISBN: 9780321629111 32

Solution for problem 6E Chapter 4

Probability and Statistics for Engineers and the Scientists | 9th Edition

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Probability and Statistics for Engineers and the Scientists | 9th Edition | ISBN: 9780321629111 | Authors: Ronald E. Walpole; Raymond H. Myers; Sharon L. Myers; Keying E. Ye

Probability and Statistics for Engineers and the Scientists | 9th Edition

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Problem 6E

The actual tracking weight of a stereo cartridge that is set to track at 3 g on a particular changer can be regarded as a continuous rv X ? ?with pdf a.? ketch the graph of ?f(? ? . b.? ?Find the value of ?k?. c.? ?What is the probability that the actual tracking weight is greater than the prescribed weight? d.? ?What is the probability that the actual weight is within .25 g of the prescribed weight? e.? ?What is the probability that the actual weight differs from the prescribed weight by more than .5 g?

Step-by-Step Solution:
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Problem 6E Answer: Step1: We have the actual tracking weight of a stereo cartridge that is set to track at 3 g on a particular changer can be regarded as a continuous rv X w ith pdf We need to find, a. Sketch the graph of f(x). b. Find the value of k. c. What is the probability that the actual tracking weight is greater than the prescribed weight d. What is the probability that the actual weight is within .25 g of the prescribed weight e. What is the probability that the actual weight differs from the prescribed weight by more Than 0.5 g Step2: a). Consider, f(x) = k[1 (x 3) ], x = 2,3,4. When x = 2 When x = 3, When x = 4, b). Consider, F (x) = k [1 (x 3) ] Integrate above equation with respect to x then we get by taking limits from 0 to 2 4 4 2 P(2X 4) = f(x)dx= k[1 (x 3) ]dx 2 2 4 = k [ (x 3) ]dx 2 4 4 2 = k 1x (x 3) ]dx 2 2 3 = k [x - (x3) ]4 3 2 (43)3 (23) = k [(4 - 3 ) - (2 - 3 ) ] 11 7 = k [ 3 3 ] 4 = k 3 k = 3 4 Therefore, the value of k is 0.7500. Step3: c). 4 4 P(X >1) = f(x)x = k[1 (x 3) ]dx 2 3 3 4 2 = k [ (x 3) ]dx 3 4 4 2 = k 1x (x...

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Chapter 4, Problem 6E is Solved
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Textbook: Probability and Statistics for Engineers and the Scientists
Edition: 9
Author: Ronald E. Walpole; Raymond H. Myers; Sharon L. Myers; Keying E. Ye
ISBN: 9780321629111

This textbook survival guide was created for the textbook: Probability and Statistics for Engineers and the Scientists, edition: 9. This full solution covers the following key subjects: weight, actual, Probability, prescribed, tracking. This expansive textbook survival guide covers 18 chapters, and 1582 solutions. The full step-by-step solution to problem: 6E from chapter: 4 was answered by , our top Statistics solution expert on 05/06/17, 06:21PM. Since the solution to 6E from 4 chapter was answered, more than 2098 students have viewed the full step-by-step answer. Probability and Statistics for Engineers and the Scientists was written by and is associated to the ISBN: 9780321629111. The answer to “The actual tracking weight of a stereo cartridge that is set to track at 3 g on a particular changer can be regarded as a continuous rv X ? ?with pdf a.? ketch the graph of ?f(? ? . b.? ?Find the value of ?k?. c.? ?What is the probability that the actual tracking weight is greater than the prescribed weight? d.? ?What is the probability that the actual weight is within .25 g of the prescribed weight? e.? ?What is the probability that the actual weight differs from the prescribed weight by more than .5 g?” is broken down into a number of easy to follow steps, and 97 words.

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