Solution Found!
Neopentyl alcohol, reacts with concentrated HBr to give
Chapter 3, Problem 15P(choose chapter or problem)
QUESTION:
Neopentyl alcohol, \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CCH}_{2} \mathrm{OH}\), reacts with concentrated \(H B r\) to give 2-bromo-2-methylbutane, a rearranged product. Propose a mechanism for the formation of this product.
Equation Transcription:
Text Transcription:
(CH_3)_3CCH_2OH
HBr
Questions & Answers
QUESTION:
Neopentyl alcohol, \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CCH}_{2} \mathrm{OH}\), reacts with concentrated \(H B r\) to give 2-bromo-2-methylbutane, a rearranged product. Propose a mechanism for the formation of this product.
Equation Transcription:
Text Transcription:
(CH_3)_3CCH_2OH
HBr
ANSWER:
Step 1 of 2
Mechanism for the formation of 2-bromo-2-methylbutane from neopentyl alcohol is given below.