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Perform each conversion.(a) 345 Cal to kilowatt-hours(b) 23 J to calories(c) 5.7 × 103 J

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 54P Chapter 3

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 54P

Problem 54P

Perform each conversion.

(a) 345 Cal to kilowatt-hours

(b) 23 J to calories

(c) 5.7 × 103 J to kilojoules

(d) 326 kJ to joules

Step-by-Step Solution:

Problem 54P

Perform each conversion.

(a) 345 Cal to kilowatt-hours

(b) 23 J to calories

(c) 5.7 × 103 J to kilojoules

(d) 326 kJ to joules

                                                             Step by step solution

Step 1 of 4

(a)

From the given - 345 cal

Let’s convert the calories to joules.


                                             

Hence, 345 Cal is equal to 1443480 joules.

Let’s convert calories to kWh.

                                               

Therefore, 345 Calories is equal to 0.40 kWh.

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Step 2 of 4

Chapter 3, Problem 54P is Solved
Step 3 of 4

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Perform each conversion.(a) 345 Cal to kilowatt-hours(b) 23 J to calories(c) 5.7 × 103 J