×

> > > > Problem 69P

# is found in Earth's crust as several different iron ## Problem 69P Chapter 6

Introductory Chemistry | 5th Edition

• 2901 Step-by-step solutions solved by professors and subject experts
• Get 24/7 help from StudySoup virtual teaching assistants Introductory Chemistry | 5th Edition

4 5 0 367 Reviews
18
4
Problem 69P

Problem 69

Iron is found in Earth's crust as several different iron compounds. Calculate the mass (in kg) of each compound that contains 1.0 × 103 kg of iron.

(a) Fe2O3 (hematite)

(b) Fe3O4 (magnetite)

(c) FeCO3 (siderite)

Step-by-Step Solution:

Solution 69P

Step 1:

(a) Fe2O3 (hematite)

Molecular mass of hematite is 159.69 g/mol = 0.15969 kg/mol

The given mass of Iron = 1.0 × 103 kg,

Hence the mass in kg = given mass / molecular mass = 1.0 × 103 /0.15969  = 6373.48

Step 2:

(b)Fe3O4 (magnetite)

Molecular mass of Fe3O4 is 231.533 g/mol = 0.231533 kg/mol

The given mass of Iron = 1.0 × 103 kg,

Hence the mass in kg = given mass / molecular mass = 1.0 × 103 /0.231533  = 4319.03

Step 3 of 3

##### ISBN: 9780321910295

Unlock Textbook Solution

is found in Earth's crust as several different iron

×
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 6 - Problem 69p

Get Full Access to Introductory Chemistry - 5 Edition - Chapter 6 - Problem 69p