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is found in Earth's crust as several different iron

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Problem 69P Chapter 6

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 69P

Problem 69

Iron is found in Earth's crust as several different iron compounds. Calculate the mass (in kg) of each compound that contains 1.0 × 103 kg of iron.

(a) Fe2O3 (hematite)

(b) Fe3O4 (magnetite)

(c) FeCO3 (siderite)

Step-by-Step Solution:

Solution 69P

Step 1:

(a) Fe2O3 (hematite)

Molecular mass of hematite is 159.69 g/mol = 0.15969 kg/mol

The given mass of Iron = 1.0 × 103 kg,

Hence the mass in kg = given mass / molecular mass = 1.0 × 103 /0.15969  = 6373.48

Step 2:

(b)Fe3O4 (magnetite)

Molecular mass of Fe3O4 is 231.533 g/mol = 0.231533 kg/mol

The given mass of Iron = 1.0 × 103 kg,

Hence the mass in kg = given mass / molecular mass = 1.0 × 103 /0.231533  = 4319.03

Step 3 of 3

Chapter 6, Problem 69P is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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