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Write complete ionic and net ionic equations for each of

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 77P Chapter 7

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 77P

PROBLEM 77P

Write complete ionic and net ionic equations for each of the reactions in Problem.

Problem

Write a molecular equation for the precipitation reaction that occurs (if any) when each pair of solutions is mixed. If no reaction occurs, write NO REACTION.

(a) sodium carbonate and lead(II) nitrate

(b) potassium sulfate and lead(II) acetate

(c) copper(II) nitrate and barium sulfide

(d) calcium nitrate and sodium iodide

Step-by-Step Solution:

Solution 77P

Here, we are going to write complete ionic and net ionic equations for the given reactions.

Step 1:

Net ionic equation shows only those chemical species which are taking part in a chemical reaction. while writing the ionic equation, we write out all the soluble compounds as ions and eliminate ions common to both the reactants and products. This will give us the net ionic equation.

Step 2:

When sodium carbonate and lead(II) nitrate are mixed, sodium nitrate and lead carbonate are formed. The balanced molecular equation for the reaction is:

                Na2CO3(aq) + Pb(NO3)2(aq) → 2NaNO3(aq) + PbCO3(s)↓

Converting the soluble compounds into ions, we get the complete ionic equation.Thus, the complete ionic equation for the above reaction is:

        2Na+(aq) + CO32-(aq) + Pb2+(aq) + 2NO3-(aq) → PbCO3(s)↓ + 2Na+(aq) + 2NO3-(aq)

Here, Na+ and NO3- behaves as spectator ion(ion existing in the same form in both side of the reaction.) and can be eliminated. Thus, the net ionic equation is:

                        Pb2+(aq) + CO32-(aq) → PbCO3(s)↓

Step 3:

    b)         When potassium sulfate and lead(II) acetate are mixed, potassium acetate and lead sulfate are formed. The balanced molecular equation for the reaction is:

                K2SO4(aq) + Pb(CH3COO)2(aq) → 2CH3COOK(aq) + PbSO4(s)↓

Converting the soluble compounds into ions, we get the complete ionic equation.Thus, the complete ionic equation for the above reaction is:

2K+(aq) + SO42-(aq) + Pb2+(aq) + 2CH3COO-(aq) → PbSO4(s)↓ + 2K+(aq) + 2CH3COO-(aq)

Here, Na+ and CH3COO- behaves as spectator ion and can be eliminated. Thus, the net ionic equation is:

                        Pb2+(aq) + SO42-(aq) → PbSO4(s)↓

Step 4 of 5

Chapter 7, Problem 77P is Solved
Step 5 of 5

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

The answer to “Write complete ionic and net ionic equations for each of the reactions in Problem. a molecular equation for the precipitation reaction that occurs (if any) when each pair of solutions is mixed. If no reaction occurs, write NO REACTION.(a) sodium carbonate and lead(II) nitrate(b) potassium sulfate and lead(II) acetate(c) copper(II) nitrate and barium sulfide(d) calcium nitrate and sodium iodide” is broken down into a number of easy to follow steps, and 59 words. This full solution covers the following key subjects: Write, nitrate, reaction, occurs, sodium. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. The full step-by-step solution to problem: 77P from chapter: 7 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. Since the solution to 77P from 7 chapter was answered, more than 389 students have viewed the full step-by-step answer.

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