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Sulfuric acid can dissolve aluminum metal according to the reaction:2 Al(s) + 3

Chapter 8, Problem 41P

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QUESTION:

Sulfuric acid can dissolve aluminum metal according to the reaction:

 

 

\(2 \mathrm{Al}(\mathrm{s})+3 \mathrm{H}_{2} \mathrm{SO}_{4}(a q) \rightarrow \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}(a q)+3 \mathrm{H}_{2}(g)\)

 

 

Suppose you wanted to dissolve an aluminum block with a mass of 22.5 g. What minimum amount of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) in grams do you need? How many grams of \(\mathrm{H}_{2}\) gas will be produced by the complete reaction of the aluminum block?

 

Questions & Answers

QUESTION:

Sulfuric acid can dissolve aluminum metal according to the reaction:

 

 

\(2 \mathrm{Al}(\mathrm{s})+3 \mathrm{H}_{2} \mathrm{SO}_{4}(a q) \rightarrow \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}(a q)+3 \mathrm{H}_{2}(g)\)

 

 

Suppose you wanted to dissolve an aluminum block with a mass of 22.5 g. What minimum amount of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) in grams do you need? How many grams of \(\mathrm{H}_{2}\) gas will be produced by the complete reaction of the aluminum block?

 

ANSWER:

Step 1 of 3

The equation for the reaction between sulfuric acid and aluminum is

Mass of the aluminum block needed to be dissolved by sulfuric acid is .

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