Calculate the concentration of each solution in mass percent.(a) 41.2 g C12H22O11 in 498

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

ISBN: 9780321910295 34

Solution for problem 41P Chapter 13

Introductory Chemistry | 5th Edition

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Problem 41P

Calculate the concentration of each solution in mass percent.

(a) 41.2 g C12H22O11 in 498 g H2O

(b) 178 mg C6H12O6 in 4.91 g H2O

Step-by-Step Solution:

Step 1 of 3

Answer :

(a) 41.2 g C12H22O11 in 498 g H2O

Mass %= mass of solute /mass of solution*100

=4.12/498*100

=0.82

(b) 178 mg C6H12O6 in 4.91 g H2O

Mass %= mass of solute /mass of solution*100

=178/4.91*100

=3625

Mass %= mass of solute /mass of solution*100

=7.55/155*100

=4.87

Step 2 of 3

Chapter 13, Problem 41P is Solved

Step 3 of 3

Textbook: Introductory Chemistry

Edition: 5

Author: Nivaldo J Tro

ISBN: 9780321910295

Since the solution to 41P from 13 chapter was answered, more than 3349 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 41P from chapter: 13 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. This full solution covers the following key subjects: calculate, concentration, mass, nacl, solution. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. The answer to “Calculate the concentration of each solution in mass percent.(a) 41.2 g C12H22O11 in 498 g H2O(b) 178 mg C6H12O6 in 4.91 g H2O(c) 7.55 g NaCl in 155 g H2O” is broken down into a number of easy to follow steps, and 30 words.