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Solved: Complete the tableMass SoluteMass SolventMass

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 46P Chapter 13

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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2
Problem 46P

Complete the table

Mass Solute

Mass Solvent

Mass Solution

Mass Percent

2.55 g

25.0 g

_____

_____

_____

45.8 g

_____

3.8%

1.38 g

_____

27.2 g

_____

23.7 g

_____

_____

5.8%

Step-by-Step Solution:

Solution 46P :

Step 1:

Formula to find mass percent :

        Mass percent =  100 %

Mass Solution = Mass solute + Mass solvent

Let’s consider 1st row :

Mass solute = 2.55 g

Mass solvent = 25.0 g

Mass Solution = ?

Mass percent = ?

        Mass solution = 2.55 g + 25.0 g

        Mass solution = 27.55 g

        Mass percent =  100 %

        Mass percent = 9.25 %

Step 2:

Mass solvent = 45.8 g

Mass percent = 3.8 %

Mass solute = ?

Mass solution = ?

We know, Mass percent =  100 %

        Therefore,  100 % = 3.8 %                [Mass solute is considered as ‘x’ ]

        Cross multiplying, we get :

                x  100 % = 3.8 % (x+ 45.8)

                100 x = 3.8 x + (3.8  45.8)

                100 x - 3.8 x = 3.8  45.8

x(100 - 3.8) = 174.04

                x =

                x = 1.809 g

Hence, Mass solute = 1.809 g

Now, let’s calculate mass solvent :

Mass solution = Mass solute + Mass solvent

                = 1.809 g + 45.8 g

Mass solution        = 47.60 g

Step 3:

Now, let’s consider 3rd row :

Mass solute = 1.38 g

Mass solution = 27.2 g

Mass solvent = ?

Mass percent = ?

        Mass solvent = Mass solution - Mass solute

                          = 27.2 g - 1.38 g

Mass solvent =  25.82 g

Mass percent = 100 %

Mass percent  = 5.07 %

Step 4 of 5

Chapter 13, Problem 46P is Solved
Step 5 of 5

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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