Problem 61P

Calculate the molarity of each solution.

(a) 22.6 g of C12H22O11 in 0.442 L of solution

(b) 42.6 g of NaCl in 1.58 L of solution

(c) 315 mg of C6H12O2 in 58.2 mL of solution

Answer :

(a) 22.6 g of C12H22O11 in 0.442 L of solution

We know that

Molarity = mass /liters.

=22.6 g /0.422 L.

=53.55 M.

(b) 42.6 g of NaCl in 1.58 L of solution

We know that

Molarity = mass /liters.

=42.6 /1.58 L.

=26.96 L.

(c) 315 mg of C6H12O2 in 58.2 mL of solution

We know that

Molarity = mass /liters.

Conversion of mL to liters takes place here

58.2 mL=0.0582 L

=315/0.0582 L

= 5412.37 M.