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General, Organic, and Biological Chemistry: Structures of Life | 4th Edition | ISBN: 9780321750891 | Authors: Karen C. Timberlake
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Solution: A nucleus is shown with protons and neutrons.

Chapter 4, Problem 49UTC

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QUESTION:

A nucleus is shown with protons and neutrons. proton neutonCarbon dating of small bits of charcoal used in cave paintings has determined that some of the paintings are from 10 000 to 30 000 y old. Carbon-14 has a half-life of 5730 y. In a 1 ?g-sample of carbon from a live tree, the activity of carbon-14 is 6.4 ?Ci. If researchers determine that 1 ?g of charcoal from a prehistoric cave painting in France has an activity of 0.80 ?Ci, what is the age of the painting? The technique of carbon dating is used to determine the age of ancient cave paintings.

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QUESTION:

A nucleus is shown with protons and neutrons. proton neutonCarbon dating of small bits of charcoal used in cave paintings has determined that some of the paintings are from 10 000 to 30 000 y old. Carbon-14 has a half-life of 5730 y. In a 1 ?g-sample of carbon from a live tree, the activity of carbon-14 is 6.4 ?Ci. If researchers determine that 1 ?g of charcoal from a prehistoric cave painting in France has an activity of 0.80 ?Ci, what is the age of the painting? The technique of carbon dating is used to determine the age of ancient cave paintings.

ANSWER:

Solution 49UTCStep 1 of 2:Here, we are asked to calculate the age of the painting.Given:Half life of carbon -14 = 5730 y.Activity of C-14 = 6.4 Ci.Activity of charcoal = 0.80 Ci.Age of painting = We know formula for radioactive decay:ln () = - kt Where Nt = activity at time t. No = original activity k = decay constantWe also know that t1/2 = 0.693 / k. k = 0.693 / t1/2 = = 0.000121

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