Solution Found!
a. Draw the products of the following reactions: b. Which
Chapter 2, Problem 22P(choose chapter or problem)
a. Draw the products of the following reactions:
A \(\mathrm{HC} \equiv \mathrm{CH}+\mathrm{CH}_{3} \overline{\mathrm{C}} \mathrm{H}_{2} \rightleftharpoons\)
B \(H_{2} \mathrm{C}=\mathrm{CH}_{2}+H C \equiv \mathrm{C}^{-} \rightleftharpoons\)
C \(\mathrm{CH}_{3} \mathrm{CH}_{3}+\mathrm{H}_{2} \mathrm{C}=\overline{\mathrm{C}} \mathrm{H} \rightleftharpoons\)
b. Which of the reactions favor formation of the products?
Equation Transcription:
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Text Transcription:
HC trigram CH+CH_3 overline C H_2 right left harpoons
H_2 C=CH_2 + HC trigram C^- right left harpoons
CH_3 CH_3 + H_2 C = overline C H right left harpoons
Questions & Answers
QUESTION:
a. Draw the products of the following reactions:
A \(\mathrm{HC} \equiv \mathrm{CH}+\mathrm{CH}_{3} \overline{\mathrm{C}} \mathrm{H}_{2} \rightleftharpoons\)
B \(H_{2} \mathrm{C}=\mathrm{CH}_{2}+H C \equiv \mathrm{C}^{-} \rightleftharpoons\)
C \(\mathrm{CH}_{3} \mathrm{CH}_{3}+\mathrm{H}_{2} \mathrm{C}=\overline{\mathrm{C}} \mathrm{H} \rightleftharpoons\)
b. Which of the reactions favor formation of the products?
Equation Transcription:
☰⇌
☰⇌
⇌
Text Transcription:
HC trigram CH+CH_3 overline C H_2 right left harpoons
H_2 C=CH_2 + HC trigram C^- right left harpoons
CH_3 CH_3 + H_2 C = overline C H right left harpoons
ANSWER:
Solution:
Here we have to complete the given chemical reactions.
Step 1
(a)
A.
(Acetylene) (Carbanion) (carbanion) (Ethane)
(Acid) (Base) (Conjugate acid) (Conjugate base)