Solution Found!
For a reaction carried out at 25 oC with an equilibrium
Chapter 5, Problem 57P(choose chapter or problem)
Problem 57P
For a reaction carried out at 25 oC with an equilibrium constant of 1 × 10−3, in order to increase the equilibrium constant by a factor of 10:
a. How much must ΔGo change?
b. How much must ΔHo change if ΔSo = 0 kcal mol-1 K-1?
c. How much must ΔSo change if ΔHo = 0 kcal mol-1?
Questions & Answers
QUESTION:
Problem 57P
For a reaction carried out at 25 oC with an equilibrium constant of 1 × 10−3, in order to increase the equilibrium constant by a factor of 10:
a. How much must ΔGo change?
b. How much must ΔHo change if ΔSo = 0 kcal mol-1 K-1?
c. How much must ΔSo change if ΔHo = 0 kcal mol-1?
ANSWER:
Solution 57P
Step 1 of 3:
Here, we are asked to find how much change in free energy, standard enthalpy and entropy is required to increase the equilibrium constant by a factor of 10 for a reaction.
Given:
T = 25 oC = 298 K
Keq = 1 × 10−3
(a).
Here, we are asked how much must ΔGo change.
We know,
Go = _ RT ln Keq
= - 1.98610-3
298 K
ln (10)
= - 1.98610-3
298 K
2.3
= - 1.36 kcal/mol
Hence, ΔGo must change by -1.36 kcal/mol to increase the Keq by a factor of 10.