cis ?2?Butene isomerizes to trans-2-butene via the

Chapter 10, Problem 102E

(choose chapter or problem)

Get Unlimited Answers
QUESTION:

cis-2-Butene isomerizes to trans-2-butene via the reaction

a. If isomerization requires breaking the \(\pi\) bond, what minimum energy is required for isomerization in J/mol? In J/molecule?

b. If the energy for isomerization came from light, what minimum frequency of light would be required? In what portion of the electromagnetic spectrum does this frequency lie?

Questions & Answers

QUESTION:

cis-2-Butene isomerizes to trans-2-butene via the reaction

a. If isomerization requires breaking the \(\pi\) bond, what minimum energy is required for isomerization in J/mol? In J/molecule?

b. If the energy for isomerization came from light, what minimum frequency of light would be required? In what portion of the electromagnetic spectrum does this frequency lie?

ANSWER:

Problem 102Ecis-2-Butene isomerizes to trans-2-butene via the following reaction:a. If isomerization requires breaking the pi bond, what minimum energy is required forisomerization in J/mol In J/moleculeb. If the energy for isomerization comes from light, what minimum frequency of light isrequired In what portion of the electromagnetic spectrum does this frequency lie Step by step solutionStep 1 of 2(a)Consider the following reaction:The bond energy of the C=C isThis bond emery includes both and bonds.The bond energy of C-C, isThe isomerization requires breaking of the bond.Therefore, the energy required to breaking the x bond is,\nConvert the energy units using the conversion factor given below. 1 kJ = 1000 JThen,One mole of any substance contains Avogadro's number of molecules.since each molecule of cis 2 - Butene contains only one C = C bond, calculate the energyrequired to break one C = C bond as follows:Therefore, the energy required for isomerization is, or____________________________________________________________________________

Add to cart


Study Tools You Might Need

Not The Solution You Need? Search for Your Answer Here:

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back